The coordinates of point O are (0, 0), and the coordinates of point C are (6, 9). It follows that the slope of the line that contains these two points is $\frac{9 - 0}{6 - 0} = \frac{3}{2}$.

The y-intercept of any line through point O is 0. Therefore, an equation of the line that contains points O and C is $y = \frac{3}{2}x$.
The correct response: d

Calculate the slope between the points and use it to determine the equation.

The slope between the point (-40, -40) and (140, 60) is $\frac{60-(-40)}{140-(-40)} = \frac{100}{180} = \frac{5}{9}$.

The equation with a slope of 5/9 passing through the point (140, 60) is $y - 60 = \frac{5}{9}(x - 140)$.

Simplify the equation by multiplying each side by 9.

Distribute on the left side of the equation.

Add 540 to each side.

540 can be written as 5(108). Factor the 5 from both terms on the right side of the equation.

Combine like terms inside the parentheses.

Divide each side of the equation by 9 to get the answer.

$y = \frac{5}{9}(x - 32)$
The correct response: b

The y-intercept is a point on the y-axis.

Every point on the y-axis has an x-value of zero.

To find the y-intercept, replace x with zero and solve for y.

4(0) - 2y = 8

-2y = 8

y = 8/(-2) = -4

The y-intercept is -4.
The correct response: d